minorticks_on() ax.contour(x,y, x**2 + 2.*x*y +y**2 - 8.*x, [0],linewidths=1.5,colors='r') ax.text(1.75,-4.5,r'$x^2+2xy+y^2-8x=0$',color='r') ax.arrow(.5...
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1 September 2011 Source Own work Author Krishnavedala Other versions Graph of Conic x 2 + 2 x y + y 2 − 8 x = 0 {\displaystyle x^{2}+2xy+y^{2}-8x=0}...